Solve Trigonometric Equations, Graph Trigonometric Functions, And Discuss Laboratory Categories In Mathematics.

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a. Solving 2cos2x+sinx=12\cos^2x + \sin x = 1 for 0x2π0 \le x \le 2\pi

When tackling trigonometric equations, the key is often to express the equation in terms of a single trigonometric function. In this instance, we have an equation involving both cosine and sine: 2cos2x+sinx=12\cos^2x + \sin x = 1. Our main keyword here is solving trigonometric equations. To solve this, we can utilize the Pythagorean identity, which states that sin2x+cos2x=1\sin^2x + \cos^2x = 1. This allows us to express cos2x\cos^2x as 1sin2x1 - \sin^2x. Substituting this into our equation, we get:

2(1sin2x)+sinx=12(1 - \sin^2x) + \sin x = 1

Expanding and rearranging the terms, we obtain a quadratic equation in terms of sinx\sin x:

22sin2x+sinx=12 - 2\sin^2x + \sin x = 1

2sin2xsinx1=02\sin^2x - \sin x - 1 = 0

Now, let's make a substitution to simplify the equation further. Let y=sinxy = \sin x. The equation then becomes:

2y2y1=02y^2 - y - 1 = 0

This is a standard quadratic equation that can be factored as follows:

(2y+1)(y1)=0(2y + 1)(y - 1) = 0

Setting each factor equal to zero gives us two possible values for yy:

2y+1=0y=122y + 1 = 0 \Rightarrow y = -\frac{1}{2}

y1=0y=1y - 1 = 0 \Rightarrow y = 1

Now, we substitute back sinx\sin x for yy:

sinx=12\sin x = -\frac{1}{2}

sinx=1\sin x = 1

For sinx=12\sin x = -\frac{1}{2}, we need to find the angles xx in the interval 0x2π0 \le x \le 2\pi where the sine function has this value. Sine is negative in the third and fourth quadrants. The reference angle for sin1(12)\sin^{-1}(\frac{1}{2}) is π6\frac{\pi}{6}. Therefore, the solutions in the given interval are:

x=π+π6=7π6x = \pi + \frac{\pi}{6} = \frac{7\pi}{6}

x=2ππ6=11π6x = 2\pi - \frac{\pi}{6} = \frac{11\pi}{6}

For sinx=1\sin x = 1, we need to find the angles xx in the interval 0x2π0 \le x \le 2\pi where the sine function equals 1. This occurs at:

x=π2x = \frac{\pi}{2}

Thus, the solutions for the equation 2cos2x+sinx=12\cos^2x + \sin x = 1 in the interval 0x2π0 \le x \le 2\pi are x=π2,7π6,11π6x = \frac{\pi}{2}, \frac{7\pi}{6}, \frac{11\pi}{6}. These values represent the points where the original trigonometric equation holds true within the specified domain. Understanding these steps is crucial for solving various trigonometric problems.

b. Solving 5cos2x=43sin2x5\cos^2x = 4 - 3\sin^2x for 180<x<180-180^\circ < x < 180^\circ

This equation, 5cos2x=43sin2x5\cos^2x = 4 - 3\sin^2x, also requires us to express it in terms of a single trigonometric function. The interval given is 180<x<180-180^\circ < x < 180^\circ, which is equivalent to (π,π)(-\pi, \pi) in radians. To solve this, we again use the Pythagorean identity sin2x+cos2x=1\sin^2x + \cos^2x = 1. We can express sin2x\sin^2x as 1cos2x1 - \cos^2x. Substituting this into our equation, we get:

5cos2x=43(1cos2x)5\cos^2x = 4 - 3(1 - \cos^2x)

Expanding and simplifying the equation, we have:

5cos2x=43+3cos2x5\cos^2x = 4 - 3 + 3\cos^2x

5cos2x=1+3cos2x5\cos^2x = 1 + 3\cos^2x

Subtracting 3cos2x3\cos^2x from both sides gives:

2cos2x=12\cos^2x = 1

Dividing by 2, we get:

cos2x=12\cos^2x = \frac{1}{2}

Taking the square root of both sides, we find:

cosx=±12=±22\cos x = \pm\frac{1}{\sqrt{2}} = \pm\frac{\sqrt{2}}{2}

Now, we need to find the angles xx in the interval 180<x<180-180^\circ < x < 180^\circ where cosx\cos x is either 22\frac{\sqrt{2}}{2} or 22-\frac{\sqrt{2}}{2}.

For cosx=22\cos x = \frac{\sqrt{2}}{2}, the reference angle is 4545^\circ. In the given interval, cosine is positive in the first and fourth quadrants. Therefore, the solutions are:

x=45x = 45^\circ

x=45x = -45^\circ

For cosx=22\cos x = -\frac{\sqrt{2}}{2}, the reference angle is still 4545^\circ, but cosine is negative in the second and third quadrants. Therefore, the solutions are:

x=18045=135x = 180^\circ - 45^\circ = 135^\circ

x=135x = -135^\circ

Thus, the solutions for the equation 5cos2x=43sin2x5\cos^2x = 4 - 3\sin^2x in the interval 180<x<180-180^\circ < x < 180^\circ are x=135,45,45,135x = -135^\circ, -45^\circ, 45^\circ, 135^\circ. These angles satisfy the original equation within the specified domain.

Graphing trigonometric functions involves understanding the transformations applied to the basic cosine or sine functions. Here, we need to graph the function f(x)=3cos(2xπ)f(x) = -3\cos(2x - \pi) on the interval 2πx2π-2\pi \le x \le 2\pi. This function is a transformation of the basic cosine function y=cosxy = \cos x. Let's break down the transformations step by step:

  1. Amplitude: The amplitude is the absolute value of the coefficient of the cosine function, which is 3=3|-3| = 3. This means the function's maximum value is 3 and its minimum value is -3.

  2. Horizontal Stretch/Compression: The term 2x2x inside the cosine function indicates a horizontal compression. The period of the transformed function is given by 2πB\frac{2\pi}{|B|}, where BB is the coefficient of xx. In this case, B=2B = 2, so the period is 2π2=π\frac{2\pi}{2} = \pi. This means the function completes one full cycle in an interval of length π\pi, which is half the period of the standard cosine function.

  3. Horizontal Shift (Phase Shift): The term π-\pi inside the cosine function indicates a horizontal shift. To find the phase shift, we set the argument of the cosine function equal to zero and solve for xx:

    2xπ=02x - \pi = 0

    2x=π2x = \pi

    x=π2x = \frac{\pi}{2}

    This means the graph is shifted π2\frac{\pi}{2} units to the right.

  4. Vertical Reflection: The negative sign in front of the cosine function, 3cos(2xπ)-3\cos(2x - \pi), indicates a reflection about the x-axis. This means the graph is flipped vertically.

Now, let's consider the interval 2πx2π-2\pi \le x \le 2\pi. Since the period of our function is π\pi, the function will complete four full cycles within this interval.

To sketch the graph, it's helpful to identify key points such as the maximum, minimum, and x-intercepts within one period. For the standard cosine function, these points are at 0,π2,π,3π2,2π0, \frac{\pi}{2}, \pi, \frac{3\pi}{2}, 2\pi. However, due to the transformations, these points will shift.

The phase shift of π2\frac{\pi}{2} moves the starting point of the cycle from x=0x = 0 to x=π2x = \frac{\pi}{2}. The horizontal compression by a factor of 2 means the key points are now at x=π2,3π4,π,5π4,3π2x = \frac{\pi}{2}, \frac{3\pi}{4}, \pi, \frac{5\pi}{4}, \frac{3\pi}{2} within one period. The reflection and amplitude change flip the graph and stretch it vertically by a factor of 3. Thus, the maximum value is -3 (due to reflection) and the minimum value is 3.

To graph the function accurately over the interval 2πx2π-2\pi \le x \le 2\pi, we can plot these transformed key points and sketch the cosine curve. The graph will start at x=2πx = -2\pi, go through four complete cycles, and end at x=2πx = 2\pi. The key is to understand how each transformation affects the shape and position of the basic cosine function.

a. Understanding Laboratory Discussions

Laboratory discussions are an integral part of the learning process in many scientific and technical fields. They provide a platform for students and researchers to engage in critical thinking, share their observations, and analyze results obtained from laboratory experiments. In the context of mathematics, laboratory discussions can focus on the practical applications of mathematical concepts, the verification of theorems, and the exploration of numerical methods.

The primary goal of a laboratory discussion is to foster a deeper understanding of the subject matter. This is achieved through collaborative learning, where participants can learn from each other's experiences and insights. Discussions often involve analyzing data, interpreting graphs, and formulating conclusions based on empirical evidence. The process of explaining one's reasoning and justifying conclusions is crucial for developing problem-solving skills and a comprehensive grasp of the material.

In mathematics, a laboratory discussion might revolve around the numerical solution of equations, the simulation of mathematical models, or the analysis of statistical data. For instance, students might discuss the convergence properties of iterative methods for solving nonlinear equations or the behavior of solutions to differential equations under different initial conditions. These discussions often involve the use of computational tools and software, allowing students to visualize abstract concepts and explore complex systems.

The structure of a laboratory discussion typically involves a moderator or facilitator who guides the conversation and ensures that all participants have an opportunity to contribute. The discussion often begins with a review of the experimental setup and procedures, followed by a presentation of the results. Participants then engage in a detailed analysis of the data, identifying trends, patterns, and anomalies. The discussion may also involve comparing experimental results with theoretical predictions and exploring possible sources of error.

Effective participation in laboratory discussions requires preparation and engagement. Students should review the experimental procedures and expected outcomes before the discussion. They should also come prepared to share their observations and insights, and to ask clarifying questions. Active listening is crucial for understanding the perspectives of others and contributing meaningfully to the conversation.

The benefits of laboratory discussions extend beyond the immediate learning experience. They help students develop critical thinking skills, communication skills, and the ability to work collaboratively. These skills are essential for success in many professional fields, making laboratory discussions a valuable component of education and research.

In summary, laboratory discussions play a vital role in enhancing understanding and promoting collaborative learning in mathematics and other scientific disciplines. They provide a structured environment for analyzing data, interpreting results, and formulating conclusions based on empirical evidence. By actively participating in these discussions, students can develop essential skills and gain a deeper appreciation for the subject matter. This interactive approach not only solidifies theoretical knowledge but also bridges the gap between theory and practical application, preparing students for real-world challenges and fostering a lifelong love for learning.

In addition, laboratory discussions encourage students to think critically about the limitations of experimental methods and the uncertainties associated with data collection. This critical perspective is essential for responsible scientific practice and for making informed decisions based on empirical evidence. The collaborative nature of these discussions also promotes a sense of community and shared inquiry, where students feel empowered to explore complex topics and challenge conventional wisdom. Ultimately, the goal of laboratory discussions is to cultivate a culture of intellectual curiosity and rigorous inquiry, where students are motivated to pursue knowledge and contribute to the advancement of their field.