The Sum Of A Number And Its Inverse Is Equal To Five. Find That Number.

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Introduction

In the fascinating realm of mathematics, we often encounter intriguing relationships between numbers and their inverses. One such relationship arises when we consider the sum of a number and its multiplicative inverse, also known as its reciprocal. In this article, we will delve into the scenario where the sum of a number and its multiplicative inverse equals five. We will explore the mathematical concepts involved, derive the equation, solve it to find the possible values of the number, and discuss the implications of this relationship. Understanding this concept not only enhances our mathematical prowess but also provides valuable insights into the interconnectedness of numbers.

This exploration begins with defining the core concepts: a number and its multiplicative inverse. The multiplicative inverse of a number is simply one divided by that number. For example, the multiplicative inverse of 2 is 1/2, and the multiplicative inverse of 5 is 1/5. The relationship we are examining is the sum of a number and its inverse, and in this specific case, that sum is equal to 5. This article aims to unpack this mathematical puzzle, providing a comprehensive understanding through detailed explanations and step-by-step solutions. Our goal is to make this mathematical concept accessible and engaging, demonstrating its relevance and applications in broader mathematical contexts. By the end of this article, you will have a clear understanding of how to approach similar problems and appreciate the elegance of mathematical relationships.

We will start by framing the problem algebraically, setting up an equation that represents the given condition. This involves translating the verbal statement into a mathematical expression, a crucial step in solving many mathematical problems. Once we have the equation, we will employ algebraic techniques to solve for the unknown number. This will involve manipulating the equation to isolate the variable and find its possible values. The process will showcase the power of algebraic methods in solving mathematical puzzles and highlight the importance of precision in mathematical operations. Furthermore, we will discuss the nature of the solutions obtained, considering whether they are real numbers, integers, or complex numbers, adding another layer of depth to our analysis.

Setting Up the Equation

To begin our exploration, let's represent the number in question as 'x'. The multiplicative inverse of 'x' is then 1/x. According to the problem statement, the sum of the number and its inverse is equal to five. This can be translated into a mathematical equation as follows:

x + (1/x) = 5

This equation is a fundamental expression that encapsulates the relationship we are investigating. It is a quadratic equation in disguise, and solving it requires a bit of algebraic manipulation. The next step is to transform this equation into a more standard form that we can solve using familiar methods. This involves eliminating the fraction and rearranging the terms to obtain a quadratic equation in the form of ax^2 + bx + c = 0. By doing so, we can then apply the quadratic formula or factorization techniques to find the solutions for 'x'. The initial setup of the equation is crucial as it lays the foundation for the rest of the solution process. A clear and accurate representation of the problem in algebraic form is essential for success in solving mathematical problems.

Transforming the equation x + (1/x) = 5 into a standard quadratic form is a critical step. To eliminate the fraction, we multiply every term in the equation by 'x'. This gives us:

x^2 + 1 = 5x

Now, we rearrange the terms to set the equation equal to zero, which is the standard form for a quadratic equation:

x^2 - 5x + 1 = 0

This is a quadratic equation in the form of ax^2 + bx + c = 0, where a = 1, b = -5, and c = 1. With the equation in this form, we can now proceed to solve it using various methods, such as the quadratic formula or completing the square. Recognizing and transforming equations into standard forms is a key skill in algebra, allowing us to apply known solution techniques. The quadratic form is particularly useful as it opens the door to a range of solution methods, each with its own advantages and applications. This step demonstrates the power of algebraic manipulation in simplifying equations and making them solvable.

Solving the Quadratic Equation

Now that we have the quadratic equation x^2 - 5x + 1 = 0, we can solve it using the quadratic formula. The quadratic formula is a general solution for any quadratic equation in the form ax^2 + bx + c = 0, and it is given by:

x = [-b ± √(b^2 - 4ac)] / (2a)

In our equation, a = 1, b = -5, and c = 1. Substituting these values into the quadratic formula, we get:

x = [5 ± √((-5)^2 - 4 * 1 * 1)] / (2 * 1)

Simplifying the expression under the square root:

x = [5 ± √(25 - 4)] / 2

x = [5 ± √21] / 2

Thus, we have two possible solutions for 'x':

x₁ = (5 + √21) / 2

x₂ = (5 - √21) / 2

These are the two numbers that, when added to their multiplicative inverses, result in five. The quadratic formula provides a powerful tool for solving quadratic equations, and its application here demonstrates how to find exact solutions for problems involving quadratic relationships. Understanding the quadratic formula and its application is essential for advanced mathematical studies and problem-solving.

The solutions we obtained, x₁ = (5 + √21) / 2 and x₂ = (5 - √21) / 2, are both real numbers. These numbers are irrational due to the presence of the square root of 21. To better understand these solutions, we can approximate their values to decimal form. Doing so gives us:

x₁ ≈ (5 + 4.58) / 2 ≈ 4.79

x₂ ≈ (5 - 4.58) / 2 ≈ 0.21

These approximations provide a more intuitive sense of the values of the numbers. We can verify that these solutions satisfy the original condition by adding each number to its multiplicative inverse and checking if the result is approximately 5. This verification step is crucial in ensuring the accuracy of our solutions. The fact that we obtained two distinct real solutions highlights the nature of quadratic equations, which can have two, one, or no real solutions depending on the discriminant (the value under the square root in the quadratic formula). In this case, the discriminant is positive, indicating two real solutions. This analysis of the solutions’ nature adds another layer to our understanding of the problem and its mathematical implications.

Verifying the Solutions

To ensure the accuracy of our solutions, it is crucial to verify that they indeed satisfy the original condition: x + (1/x) = 5. Let's verify each solution separately.

For x₁ = (5 + √21) / 2:

1/x₁ = 2 / (5 + √21)

To rationalize the denominator, we multiply the numerator and denominator by the conjugate (5 - √21):

1/x₁ = [2 * (5 - √21)] / [(5 + √21) * (5 - √21)]

1/x₁ = [2 * (5 - √21)] / (25 - 21)

1/x₁ = [2 * (5 - √21)] / 4

1/x₁ = (5 - √21) / 2

Now, adding x₁ and 1/x₁:

x₁ + (1/x₁) = [(5 + √21) / 2] + [(5 - √21) / 2]

x₁ + (1/x₁) = (5 + √21 + 5 - √21) / 2

x₁ + (1/x₁) = 10 / 2

x₁ + (1/x₁) = 5

For x₂ = (5 - √21) / 2:

1/x₂ = 2 / (5 - √21)

To rationalize the denominator, we multiply the numerator and denominator by the conjugate (5 + √21):

1/x₂ = [2 * (5 + √21)] / [(5 - √21) * (5 + √21)]

1/x₂ = [2 * (5 + √21)] / (25 - 21)

1/x₂ = [2 * (5 + √21)] / 4

1/x₂ = (5 + √21) / 2

Now, adding x₂ and 1/x₂:

x₂ + (1/x₂) = [(5 - √21) / 2] + [(5 + √21) / 2]

x₂ + (1/x₂) = (5 - √21 + 5 + √21) / 2

x₂ + (1/x₂) = 10 / 2

x₂ + (1/x₂) = 5

Both solutions satisfy the original equation, thus confirming their correctness. This detailed verification process showcases the importance of checking solutions in mathematical problem-solving, ensuring accuracy and reinforcing understanding of the concepts involved.

The verification process not only confirms the correctness of our solutions but also provides a deeper understanding of the relationship between a number and its multiplicative inverse. By going through the steps of rationalizing the denominator and simplifying the expressions, we reinforce our algebraic skills and gain confidence in our problem-solving abilities. This process highlights the interconnectedness of mathematical concepts and the importance of a systematic approach to problem-solving. Furthermore, it demonstrates that both solutions, x₁ and x₂, are reciprocals of each other, which is a natural consequence of the original equation. This verification exercise is a valuable learning experience, emphasizing the importance of rigor and precision in mathematics.

Implications and Further Exploration

The solutions to the equation x + (1/x) = 5 provide interesting insights into the properties of numbers and their inverses. The two solutions, x₁ = (5 + √21) / 2 and x₂ = (5 - √21) / 2, are reciprocals of each other, as we observed during the verification process. This relationship is not coincidental; it is a direct consequence of the structure of the equation. When a number and its inverse sum to a constant, the solutions will always be reciprocals of each other.

This concept can be generalized further. For any constant 'k', the equation x + (1/x) = k will yield solutions that are reciprocals. This is because if 'x' is a solution, then 1/x will also be a solution. This symmetry in the solutions is a fascinating aspect of this type of equation. Exploring this generalization can lead to a deeper understanding of the algebraic properties and symmetries inherent in mathematical relationships. It also opens the door to solving similar problems with different constants, providing a versatile problem-solving approach.

Furthermore, the nature of the solutions depends on the value of the constant 'k'. In our case, k = 5, and we obtained two distinct real solutions. However, if 'k' were less than 2 or greater than -2, the solutions would be complex numbers. This is because the discriminant (b^2 - 4ac) in the quadratic formula would be negative, leading to complex roots. Analyzing the discriminant and its impact on the nature of the solutions is a valuable exercise in understanding quadratic equations and their behavior. This broader exploration can enhance mathematical intuition and problem-solving skills, allowing for a more nuanced understanding of algebraic concepts.

Further Exploration

Consider exploring other values for the sum. For instance, what happens if the sum is 6? Or what if the sum is a negative number? How do the solutions change, and what patterns can you observe? Exploring different constants can reveal interesting variations and deepen your understanding of the underlying mathematical principles.

Another avenue for exploration is to investigate similar equations involving other algebraic relationships. For example, what if we consider the difference between a number and its inverse? Or what if we introduce additional terms or operations? These variations can lead to new and challenging problems, fostering creativity and problem-solving skills.

Conclusion

In this article, we embarked on a mathematical journey to explore the sum of a number and its multiplicative inverse equaling five. We successfully translated the problem into an algebraic equation, x + (1/x) = 5, and solved it using the quadratic formula. We found two solutions, x₁ = (5 + √21) / 2 and x₂ = (5 - √21) / 2, which we verified to be correct. Our exploration extended beyond the specific problem to consider the general relationship between a number, its inverse, and their sum.

We discussed the implications of this relationship, noting that the solutions are reciprocals of each other and that the nature of the solutions depends on the constant value of the sum. This analysis highlighted the importance of understanding the discriminant in quadratic equations and its impact on the nature of the roots. Furthermore, we suggested avenues for further exploration, such as varying the constant sum and investigating similar algebraic relationships. This encourages a deeper engagement with mathematical concepts and fosters a spirit of inquiry and discovery.

The process of solving this problem not only reinforced our algebraic skills but also provided valuable insights into mathematical problem-solving. We learned the importance of translating verbal statements into mathematical equations, applying appropriate algebraic techniques, and verifying the accuracy of our solutions. This systematic approach is applicable to a wide range of mathematical problems and is essential for success in advanced studies. The exploration of this problem has demonstrated the beauty and elegance of mathematical relationships and the power of algebraic methods in unraveling them. Mathematics is not just about numbers and equations; it is about understanding patterns, relationships, and the interconnectedness of ideas. This article has aimed to convey this broader perspective and inspire further exploration and learning.

By delving into the sum of a number and its multiplicative inverse, we have uncovered a rich tapestry of mathematical concepts and relationships. This exploration serves as a testament to the power of mathematical thinking and the joy of mathematical discovery. The journey from the initial problem statement to the final conclusion has been a valuable learning experience, highlighting the importance of perseverance, precision, and a systematic approach to problem-solving. As we conclude this article, we hope that the insights gained and the skills developed will serve as a foundation for future mathematical endeavors and a lifelong appreciation for the beauty and elegance of mathematics.